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 pyrosilver I definitely agree with you I too am using Spivak's calculus book (my class just finished chapter 2, I'm a sophomore so I'm going a little slower through the book) But yeah start by multiplying the beginning terms you have, and the end terms you have good luck!= # 3 $ % % & & d ' !Johnson & Johnson's Health for Humanity Report details the progress it's made in the past five years in driving sustainable social, environmental and economic change around the globe Now the company's looking ahead to the next five alt Read the Story

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Nj= x n and (x n)1 =1 is strictly increasing (iii)Similarly for all n2N, y n1 = x ny n 2 < y ny n 2 = y n and (y n)1 =1 is strictly decreasing (iv)The rst inequality was proven in (i) already We now look at the second inequality For n= 1, one simply needs to prove that y 2 x 2 < y 1 x 1 2 But, y 1 x 1 2 y 2 x 2 = y 1 x 1 2 y 1x 1 2I j k l m n o j p q r s t u v w x y z {} ~ v} v w x y z { } ~ y {w 0 1 2 3 4 5 6 7 8 9;NJSA 5522 Statutes Governing Horse RacingNJSA Statutes Governing Casino SimulcastingNJRC Rules and Regulations Office of the State Medical Examiner Victims of Crime Compensation Office Please note this page is under construction

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